pku acm 1183

推导过程：

1/a = (1/b + 1/c)/ (1 - 1/(b*c)) => bc-1 = a(b+c)

assume b=a+m and c=a+n (b and c is always bigger than a)

(a+m)(a+n)-1=a(a+m+a+n) => a*a+a*n+a*m+m*n-1=2*a*a+m*a+n*a => m*n=a*a+1 and then

for(m=a;m>=1;m--)

if((a*a+1)%m==0) break;

n=(a*a+1)/m

import java.util.Scanner; 
public class Main{ 
	public static void main(String[] args)throws Exception{ 
		Scanner cin=new Scanner(System.in); 
		long a=cin.nextInt(); 
		long m=0,n=0; 
		for(m=a;m>=1;m--){ 
			if((a*a+1)%m==0)break;
		} 
		n=(a*a+1)/m; 
		System.out.println(2*a+m+n); 
	}
}